TSTP Solution File: ITP001^7 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : ITP001^7 : TPTP v8.1.2. Bugfixed v7.5.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n001.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 03:37:32 EDT 2023

% Result   : Theorem 4.42s 4.64s
% Output   : Proof 4.42s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.14  % Problem    : ITP001^7 : TPTP v8.1.2. Bugfixed v7.5.0.
% 0.00/0.15  % Command    : duper %s
% 0.16/0.37  % Computer : n001.cluster.edu
% 0.16/0.37  % Model    : x86_64 x86_64
% 0.16/0.37  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.16/0.37  % Memory   : 8042.1875MB
% 0.16/0.37  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.16/0.37  % CPULimit   : 300
% 0.16/0.37  % WCLimit    : 300
% 0.16/0.37  % DateTime   : Sun Aug 27 13:15:48 EDT 2023
% 0.16/0.37  % CPUTime    : 
% 4.42/4.64  SZS status Theorem for theBenchmark.p
% 4.42/4.64  SZS output start Proof for theBenchmark.p
% 4.42/4.64  Clause #14 (by assumption #[]): Eq (∀ (V0t : Prop), Or (Eq V0t c_2Ebool_2ET) (Eq V0t c_2Ebool_2EF)) True
% 4.42/4.64  Clause #23 (by assumption #[]): Eq (Iff c_2Ebool_2EF (∀ (V0t : Prop), V0t)) True
% 4.42/4.64  Clause #39 (by assumption #[]): Eq (Not c_2Ebool_2ET) True
% 4.42/4.64  Clause #40 (by clausification #[39]): Eq c_2Ebool_2ET False
% 4.42/4.64  Clause #42 (by clausification #[23]): Or (Eq c_2Ebool_2EF False) (Eq (∀ (V0t : Prop), V0t) True)
% 4.42/4.64  Clause #47 (by clausification #[42]): ∀ (a : Prop), Or (Eq c_2Ebool_2EF False) (Eq a True)
% 4.42/4.64  Clause #562 (by clausification #[14]): ∀ (a : Prop), Eq (Or (Eq a c_2Ebool_2ET) (Eq a c_2Ebool_2EF)) True
% 4.42/4.64  Clause #563 (by clausification #[562]): ∀ (a : Prop), Or (Eq (Eq a c_2Ebool_2ET) True) (Eq (Eq a c_2Ebool_2EF) True)
% 4.42/4.64  Clause #564 (by clausification #[563]): ∀ (a : Prop), Or (Eq (Eq a c_2Ebool_2EF) True) (Eq a c_2Ebool_2ET)
% 4.42/4.64  Clause #565 (by clausification #[564]): ∀ (a : Prop), Or (Eq a c_2Ebool_2ET) (Eq a c_2Ebool_2EF)
% 4.42/4.64  Clause #566 (by forward demodulation #[565, 40]): ∀ (a : Prop), Or (Eq a False) (Eq a c_2Ebool_2EF)
% 4.42/4.64  Clause #585 (by falseElim #[566]): Eq True c_2Ebool_2EF
% 4.42/4.64  Clause #602 (by superposition #[585, 47]): ∀ (a : Prop), Or (Eq True False) (Eq a True)
% 4.42/4.64  Clause #612 (by clausification #[602]): ∀ (a : Prop), Eq a True
% 4.42/4.64  Clause #615 (by falseElim #[612]): False
% 4.42/4.64  SZS output end Proof for theBenchmark.p
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