TSTP Solution File: ITP001^7 by Duper---1.0
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% File : Duper---1.0
% Problem : ITP001^7 : TPTP v8.1.2. Bugfixed v7.5.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n001.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 03:37:32 EDT 2023
% Result : Theorem 4.42s 4.64s
% Output : Proof 4.42s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.14 % Problem : ITP001^7 : TPTP v8.1.2. Bugfixed v7.5.0.
% 0.00/0.15 % Command : duper %s
% 0.16/0.37 % Computer : n001.cluster.edu
% 0.16/0.37 % Model : x86_64 x86_64
% 0.16/0.37 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.16/0.37 % Memory : 8042.1875MB
% 0.16/0.37 % OS : Linux 3.10.0-693.el7.x86_64
% 0.16/0.37 % CPULimit : 300
% 0.16/0.37 % WCLimit : 300
% 0.16/0.37 % DateTime : Sun Aug 27 13:15:48 EDT 2023
% 0.16/0.37 % CPUTime :
% 4.42/4.64 SZS status Theorem for theBenchmark.p
% 4.42/4.64 SZS output start Proof for theBenchmark.p
% 4.42/4.64 Clause #14 (by assumption #[]): Eq (∀ (V0t : Prop), Or (Eq V0t c_2Ebool_2ET) (Eq V0t c_2Ebool_2EF)) True
% 4.42/4.64 Clause #23 (by assumption #[]): Eq (Iff c_2Ebool_2EF (∀ (V0t : Prop), V0t)) True
% 4.42/4.64 Clause #39 (by assumption #[]): Eq (Not c_2Ebool_2ET) True
% 4.42/4.64 Clause #40 (by clausification #[39]): Eq c_2Ebool_2ET False
% 4.42/4.64 Clause #42 (by clausification #[23]): Or (Eq c_2Ebool_2EF False) (Eq (∀ (V0t : Prop), V0t) True)
% 4.42/4.64 Clause #47 (by clausification #[42]): ∀ (a : Prop), Or (Eq c_2Ebool_2EF False) (Eq a True)
% 4.42/4.64 Clause #562 (by clausification #[14]): ∀ (a : Prop), Eq (Or (Eq a c_2Ebool_2ET) (Eq a c_2Ebool_2EF)) True
% 4.42/4.64 Clause #563 (by clausification #[562]): ∀ (a : Prop), Or (Eq (Eq a c_2Ebool_2ET) True) (Eq (Eq a c_2Ebool_2EF) True)
% 4.42/4.64 Clause #564 (by clausification #[563]): ∀ (a : Prop), Or (Eq (Eq a c_2Ebool_2EF) True) (Eq a c_2Ebool_2ET)
% 4.42/4.64 Clause #565 (by clausification #[564]): ∀ (a : Prop), Or (Eq a c_2Ebool_2ET) (Eq a c_2Ebool_2EF)
% 4.42/4.64 Clause #566 (by forward demodulation #[565, 40]): ∀ (a : Prop), Or (Eq a False) (Eq a c_2Ebool_2EF)
% 4.42/4.64 Clause #585 (by falseElim #[566]): Eq True c_2Ebool_2EF
% 4.42/4.64 Clause #602 (by superposition #[585, 47]): ∀ (a : Prop), Or (Eq True False) (Eq a True)
% 4.42/4.64 Clause #612 (by clausification #[602]): ∀ (a : Prop), Eq a True
% 4.42/4.64 Clause #615 (by falseElim #[612]): False
% 4.42/4.64 SZS output end Proof for theBenchmark.p
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